Answer:
y+20/5
Step-by-step explanation:
Answer:
when they are far away from each other they will move at a velocity of v∞/q = 1.84*10⁶ m/(s*C)
Step-by-step explanation:
if we assume that the charges repel according to a Coulomb's law ( we neglect any relativistic effects) , then the force of repulsion is
F rep = k*q*q/r²
where q= charge
k= Coulomb's constant
r= distance
from Newton's second law :
F rep = m*a= m*dv/dt = m*dv/dr * dr/dt = m*v*dv/dr
k*q*q/r² = m*v*dv/dr
k*q*q/(m*r²) = v*dv/dr
(k*q*q/m) ∫ r⁻² dr= ∫v*dv
-2*k*q*q/m*r = v² - v₁²
for r=r₀ , v=0 ,then
-2*k*q*q/m*r₀ = 0 - v₁²
v₁² = 2*k*q*q/m*r₀
v²= -k*q*q/(m*r) + v₁²= 2*k*q*q/m* (1/r₀-1/r)
then
v²= 2*k*q²/m* (1/r₀-1/r)
when the masses are far away from each other r→∞ , 1/r → 0, then
v∞² = 2*k*q²/(m*r₀)
v∞ = √[2*k*q²/(m*r₀)]
since
k= 8.987*10⁹ N·m²/C² , m= 1 mg = 0.001 kg , r₀= 5.3 cm = 0.053 m
v∞/q = √[[2*k/(m*r₀)] = √[2*8.987*10⁹ N·m²/C²/(0.001 kg*0.053 m)] = 1.84*10⁶ m/(s*C)
v∞/q = 1.84*10⁶ m/(s*C)
Answer: ![2-5\sqrt{6}-3\sqrt{2}](https://tex.z-dn.net/?f=2-5%5Csqrt%7B6%7D-3%5Csqrt%7B2%7D)
Step-by-step explanation:
= ![(2-5\sqrt{6} )-3\sqrt{2}](https://tex.z-dn.net/?f=%282-5%5Csqrt%7B6%7D%20%29-3%5Csqrt%7B2%7D)
= ![2-5\sqrt{6}-3\sqrt{2}](https://tex.z-dn.net/?f=2-5%5Csqrt%7B6%7D-3%5Csqrt%7B2%7D)
This expression is simplified already
Answer:
11919
Step-by-step explanation:
S base n = n over 2 [ a + ℓ] is the sysbol of sum of arithmetic progression
<h3>S = sum, a = the fist term, ℓ = the last term, n = the term that you want to find </h3>
Now :
S base n = n over 2 [a+ℓ]
S base 58 = 58 over 2 [ 6+405]
= 29 ( 411)
= 11919
Answer:
Well since he tracked the person through the communication towers he was able to gather information, with this information we can solve and find out how far this person is.
Step-by-step explanation: read above and trust