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3 years ago

What is the lower extreme and the upper extreme of the numbers 45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100

1 answer:

7 0

The lower extreme is the least value in the data set and the upper extreme is the greatest value. These two values can therefore be found directly from an ordered set of data.
Lower extreme is 45
Upper extreme is 100
Good luck

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How do you do this? I am really confused

german

Answer:

Step-by-step explanation:

ok, so this is an infinitly repeating function, so you can write it as:

sqrt(12-x)

Although, x is also equal to sqrt(12-x), so

x = sqrt(12-x), and

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x^2-12+x = 0

now just apply the quadratic formula and you're good

hope i helped :D

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2 years ago

Can someone simplify this, I just want to make sure that I’m doing what I’m doing right.

Harman [31]

Answer:

Step-by-step explanation:

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3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Arthur has decided to start saving for a new computer. His money is currently in a piggy bank at home, modeled by the function s

Leya [2.2K]

Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.

$h(x) = f(x) + g(x)$ $h(x) = f(x) - g(x)$

$h(x) = \frac{f(x)}{g(x)}$ $h(x) = f(g(x))$

And many more.

The approach or formula to use depends on the question.

In this case, the combined function is:

$f(x) = 75+ 10x$

The savings function is given as

$s(x) = 85$

The allowance function is given as:

$a(x) = 10(x - 1)$

The new function that combined his savings and his allowances is calculated as:

$f(x) = s(x) + a(x)$

Substitute values for s(x) and a(x)

$f(x) = 85 + 10(x - 1)$

Open bracket

$f(x) = 85 + 10x - 10$

Collect like terms

$f(x) = 85 - 10+ 10x$

$f(x) = 75+ 10x$