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3 years ago

PLEASE HELP WITH 7&8

Mathematics

1 answer:

lbvjy [14]3 years ago

5 0

I wrote my answer in the picture

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The equation line l is given by the equation y= 7/4x+3. line m goes through the point ( –1,4) and is perpendicular to line l whi

mr_godi [17]

We determine line m as follows:

*First, by theorem we have the following:

$m_1=-\frac{1}{m_2}$

Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:

$m_1=-\frac{1}{\frac{7}{4}}\Rightarrow m_1=-\frac{4}{7}$

So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:

$y-y_1=m_1(x-x_1)$

Here x1, y1 & m1 are the x-component of the point, the y-component of the point, and the slope of the line respectively, so we replace and solve for y:

$y-4=-\frac{4}{7}(x-(-1))\Rightarrow y-4=-\frac{4}{7}x-\frac{4}{7}$ $\Rightarrow y=-\frac{4}{7}x+\frac{24}{7}$

And that last function of y is the line m.

8 0

1 year ago

In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm. Find the area of triangle ABC.

max2010maxim [7]

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

$Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}$

Find Area :

$s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15$

$Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\$

$= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}$

$= 42 . 43 \ cm^2$

7 0

3 years ago

5 ( n - 7 ) = 2 ( n + 14 )

wariber [46]

Answer:

n=21

Step-by-step explanation:

We must find n.

Remember PEMDAS. First we must do the Parentheses. Lets do distributive property by multiplying a number that is immediately outside the parentheses with each number inside the parentheses. Lets do this one side at a time.

First lets do 5(n - 7). We get 5n - 35

Now 2(n + 14) is 2n + 28

Okay...... now we have $5n-35=2n+28$