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3 years ago

15

The inhabitants of the island of jumble use the standard kobish alphabet ($20$ letters, a through t). each word in their languag

e is $4$ letters or less, and for some reason, they insist that all words contain the letter a at least once. how many words are possible?

1 answer:

max2010maxim [7]3 years ago

4 0

We know that

<span>1. The number of all 4-letter words written using the alphabet of 20 symbols (from A to T) is
20</span><span>^4=160,000
</span><span>
2. The number of all 4-letter words written using the alphabet of 19 symbols (from B to T) is
19</span><span>^4=130,321
</span><span>
3. The difference represents exactly the number of all words of the inhabitants of the island of Jumble
difference=</span>(160,000-130,321)= 29679.

the answer is
29679

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This is the pvalue of the zscore of $X = 5252$

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