What question should you ask yourself to determine if a story is newsworthy

The world wide web was originally conceived of as a(n) _____.

Setler [38]

Hello <span>Lcedillo7073 </span>

Answer: The world wide web was originally conceived of as a(n) Internal document management system

Hope this helps
-Chris

7 0

2 years ago

Which control segment communicates with the satellites? OA master stations O B. monitoring stations O C. ground antennas D. cont

nignag [31]

Answer:

C. ground antennas

Explanation:

AKA Satellite Dishes That Communicate Just Like Direct Tv dish It is focused by a bowl-shaped parabolic dish onto a device in the center called a "feed horn", which channels the signal to a "low-noise block down converter" (LNB) which filters out unwanted interference, and sometimes converts it to yet another frequency before amplifying it and sending it to the satellite receiver

5 0

2 years ago

In JAVA please:

blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

if (keysList[i]>50){

System.out.println(itemsList[i] + " "); } }

System.out.println("");

}

Explanation:

I will explain the whole program flow.

There are two arrays here

keysList and itemsList

The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.

Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
So the program control enters the body of the loop.
In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.

IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.

In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.

IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.

In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.

IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.

In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
So the output of the above program is:

72

54

5 0

3 years ago

Have you searched Buzz Ch.at on playstore

deff fn [24]

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

3 0

2 years ago

1. Grouping Data in a Pivot Table can help you do what?

valentina_108 [34]

Answer:

1.Grouping data in a PivotTable can help you show a subset of data to analyze. For example, you may want to group an unwieldy list of dates or times (date and time fields in the PivotTable) into quarters and months, like this image. Note: The time grouping feature is new in Excel 2016.

2.Select the rows or columns you wish to grouP

On the Data tab, in the Outline group, click the Group command.

In the Group dialog box, select Rows or Columns and click OK.

3.Select the rows or columns you wish to ungroup.

On the Data tab, in the Outline group, click the Ungroup command.

In the Group dialog box, select Rows or Columns and click OK.

4.

1.Launch Microsoft Excel.

2

Browse to and open the workbook file containing the pivot table and source data for which you need filter data.

3

Select the worksheet containing the pivot tab and make it active by clicking the appropriate tab.

4

Determine the attribute by which you want to filter data in your pivot table.

The attribute should be one of the column labels from the source data that is populating your pivot table.

For example, assume your source data contains sales by product, month and region. You could choose any one of these attributes for your filter and have your pivot table display data for only certain products, certain months or certain regions. Changing the filter field would determine which values for that attribute are shown.

5

Force the Pivot Table Wizard or Field List to launch by clicking a cell inside the pivot table.

6

Drag and drop the column label field name you wish to apply as a filter to the "Report Filter" section of the pivot table field list.

This field name may already be in the "Column Labels" or "Row Labels" section.

It may be in the list of all field names as an unused field.

7

Set the filter to display one of the values for the field.

You can set the filter to display all values or only one. Click the arrow beside the filtered label and check the "Select Multiple Items" check box if you would like to select certain values for your filter.

Explanation:

PLZ MARK ME AS A BRAINLIST ;)

4 0

3 years ago