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3 years ago

If p(x)= x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)?

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

8 0

Answer:

x² - 5x + 4

Step-by-step explanation:

note that (p - q)(x) = p(x) - q(x), thus

p(x) - q(x)

= x² - 1 - 5(x - 1) ← distribute parenthesis by - 5

= x² - 1 - 5x + 5 ← collect like terms

= x² - 5x + 4

o-na [289]3 years ago

5 0

Answer:c (x^2-1)-5(x-1)

Step-by-step explanation: took test

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Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

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The number of red marbles is $n_r = 7$

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The probability of the second ball not being red is mathematically represented as

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The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

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The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

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$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

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If p(x)= x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)?​

If p(x)= x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)?