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iren [92.7K]
3 years ago
13

What is th vaule of log4 16 ?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

the vaule of log4 16 is 2

Step-by-step explanation:


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3x+2.2is equal to x=1.7
Leviafan [203]

Answer:

7.3 answer

Step-by-step explanation:

x=1.7

now

3x+2.2

3×1.7+2.2

7.3

7 0
3 years ago
How does the division rule for exponents help in understanding why anything to the zero power is 1?
Nookie1986 [14]
In the division rule you subtract the exponents<span> when </span>dividing<span> numbers with the same base. </span>One<span> rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = </span>0<span>,because </span>0/0<span> is indeterminate (it is like dividing </span>zero<span> by </span>zero<span>). No matter what number we use when it is raised to the </span>zero power<span> it will always be </span>1.
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3 years ago
Cicily wants to estimate the answer to this problem to see if her answer is reasonable.
suter [353]
I believe that the answer is A- 8600-5300
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3 0
3 years ago
Find the value of r so the line that passes through each pair of points has the given slope.
padilas [110]

Answer:

<em>- 4</em>

Step-by-step explanation:

( 3 - r ) / ( 1 + 5) = 7/6

\frac{3-r}{1+5} = \frac{7}{6} ⇒ 3 - r = 7 ⇒ r = <em>- 4</em>

7 0
3 years ago
A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a ne
velikii [3]

Answer:

M = 1/0.000121 = 8264.5 years

Step-by-step explanation:

M = − k ∫∞₀ teᵏᵗdt

To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt

∫udv = uv - ∫ vdu

u = t

du/dt = 1

du = dt

∫ dv = ∫ eᵏᵗdt

v = eᵏᵗ/k

∫udv = ∫ teᵏᵗdt

uv = teᵏᵗ/k

∫ vdu = eᵏᵗ/k

∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k

But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²

∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²

The rest of the calculation is done on paper in the image attached to this question

3 0
3 years ago
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