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snow_tiger [21]
3 years ago
15

What 3 types of technologies are used inside hard drives?

Computers and Technology
1 answer:
Elan Coil [88]3 years ago
5 0
<span>The answer is : Solid state drives, Hybrid hard drives and magnetic hard drives.   The </span>3 types of technologies that  are used inside hard drives are Solid state drives, Hybrid hard drives and magnetic hard drives.  
A solid-state drive<span> (</span>SSD<span>) is a </span>solid-state storage <span>device that uses </span>integrated circuit<span> (ic) assemblies as </span>memory<span> to store data purposely</span><span>. </span><span>A </span>hybrid drive<span>, or SSHD, is a physical </span>storage device<span> that combines a fast storage medium such</span> solid-state drive<span> (SSD) with a </span>hard disk drive<span> (HDD), with the intention of adding some of the speed of flash storage to the cost-effective storage capacity of traditional HDDs.  A Magnetic</span><span> </span>hard drive<span> </span><span>is a data storage device that uses </span>magnetic <span>storage to store and retrieve digital information using one or more rapidly rotating  </span>disks<span> (platters) coated with </span>magnetic<span> material.</span>
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8_murik_8 [283]

Answer:

#include<iostream>

#include<string>

using namespace std;

class zip_code

{

private:

int zipcode;

string get_string(int num)

{

string str="";

if(num == 0) return "11000";

if(num>7)

{

str.append("1");

num = num-7;

}

else

str.append("0");

if(num>4)

{

str.append("1");

num = num-4;

}

else

str.append("0");

if(num>2)

{

str.append("1");

num = num-2;

}

else

str.append("0");

if(num>1)

{

str.append("1");

num = num-1;

}

else

str.append("0");

str.append("0");

return str;

}

public:

zip_code(int barcode)

{

if(barcode<10000 || barcode>99999)

cout <<"Invalid Bar code passed to constructor." << endl;

else

zipcode = barcode;

}

zip_code(string barcode)

{

if(barcode.length()>27)

cout <<"Invalid Bar code passed to constructor." << endl;

else

{

int zipper = 0;

string str_local = barcode.substr(1,barcode.length()-2);

for(int i=0; i<str_local.length()-5; i+=5)

{

int local = 0;

local = 7*(str_local[i]-'0') +

       4*(str_local[i+1]-'0') +

       2*(str_local[i+2]-'0') +

       1*(str_local[i+3]-'0');

if(local == 11) local = 0;

       zipper = zipper*10 + local;

}

zipcode = zipper;

}

}

string getZipcode()

{

string str = "1";

int first = zipcode/10000;

int second = (zipcode - first*10000)/1000;

int third = (zipcode - first*10000-second*1000)/100;

int fourth = (zipcode - first*10000-second*1000-third*100)/10;

int fifith = (zipcode - first*10000-second*1000-third*100-fourth*10);

str.append(get_string(first));

str.append(get_string(second));

str.append(get_string(third));

str.append(get_string(fourth));

str.append(get_string(fifith));

str.append("1");

return str;

}

int get_zipCode()

{

return zipcode;

}

};

int main()

{

zip_code z1(123456);

zip_code z2(99504);

cout << z2.getZipcode() << endl;

system("pause");

return 0;

}

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Answer:

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Explanation:

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Answer:

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