Answer:
A) $16
B) p(x) = 16x -800
C) 69 tickets
Step-by-step explanation:
A) The total of expenses is ...
$280 +100 +20 +400 = $800
If this is covered by 50 tickets, then a ticket must provide revenue of ...
$800/50 = $16
The cost per ticket is $16.
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B) The profit is the difference between revenue and expenses. The revenue from sale of x tickets will be 16x. The expenses are fixed at 800, so the profit is ...
p(x) = 16x -800
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C) We can find the number of tickets to sell (x) in order for profit to be at least $300 by solving the inequality ...
p(x) ≥ 300
16x -800 ≥ 300 . . . . . use the expression for p(x)
16x ≥ 1100 . . . . . . . . . add 800
x ≥ 68.75 . . . . . . . . . . divide by 16 . . . (the least satisfactory integer is 69)
In order to raise at least $300, the number of tickets sold must be at least 69.
Answer:
Step-by-step explanation:
S = 2
T = -2
so in S - T = 4. 2 - -2 = 4
IN S + T = 2 S + - 2 = 2
A line segment is a line with two end points. Hope this helped! Good luck! :)
