3. 3^10
4. 1/2 n^2
5. 1/n^3
6. 9r^3 / 5g^2
7. 10n / c^3
8. 3y^2 / g^2
Step-by-step explanation:
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Answer:
The horizontal distance from the center is 49.3883 feet
Step-by-step explanation:
The equation of an ellipse is equal to:

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.
Then, replacing a by 106/2 and b by 33.9, we get:

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

So, the horizontal distance from the center is 49.3883 feet
Answer:
Here's what I get.
Step-by-step explanation:
The rule is (x, y) ⟶ (x + 3, y + 4).
That means you must move each point three units to the right and four units up. Thus,
M(-3, -2) ⟶ M'(0, 2)
N(-1, 4) ⟶ N'(2, 8)
P(2, 4) ⟶ P'(5, 8)
Q(4, -2) ⟶ Q'(7, 2)
Your quadrilateral is a trapezoid. Both MNPQ and its image M'N'P'Q' are shown in the Figure below.
Answer:
-9yъ
Step-by-step explanation:
Since they have the same variables (yъ) then you can add or subtract,
=-8yъ -yъ
= -9yъ