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NNADVOKAT [17]
2 years ago
9

Explain how to write 50,000 using exponents. Answer can only be one number but the answer can have as much exponents as wanted

Mathematics
1 answer:
Oksana_A [137]2 years ago
5 0
The examples of 50,000 written as an exponent are as follows (but not limited to):

500 * 10^2
50 * 10^3
5 * 10^4
0,5 * 10^5

Doublecheck (optional):

500 * 10^2 = 500 * 100 = 50,000
50 * 10^3 = 50 * 1000 = 50,000
5 * 10^4 = 5 * 10000 = 50,000
0,5 * 10^5 = 0,5 * 100000 = 50,000
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Find ​(a) PQ to the nearest tenth and ​(b) the coordinates of the midpoint of __ pq.
lutik1710 [3]

Answer:

a) 5units

b) (4.5, 4)

Step-by-step explanation:

Let the coordinate of P and Q be P(3, 2) and Q(6, 6)

PQ can be gotten using the distance formula;

PQ =√(6-2)²+(6-3)²

PQ = √4²+3²

PQ =√16+9

PQ =√25

PQ = 5units

Midpoint M is  expressed as;

M(X, Y) = {(x1+x2)/2, y1+y2/2}

X = x1+x2/2

X = 3+6/2

X= 9/2

X = 4.5

Similarly;

Y = y1+y2/2

Y = 2+6/2

Y = 8/2

Y = 4

Hence the midpoint of PQ is (4.5, 4)

4 0
2 years ago
A concert ticket that originally cost$46.50 is on sale for $ 38.75. What is the percent of decrease ,rounded to the nearest tent
docker41 [41]
The answer would be%16.5
6 0
3 years ago
14. Given: 5x + 4y = 24, x + 7y= 11; Prove: y= 1<br> Statements<br> reasons
Semenov [28]

Answer:

Step-by-step explanation:

We can use the process of elimination as

5x + 4y = 24

5(x + 7y = 11) —>          5x + 35y = 55

5x + 4y = 24

-(5x + 35y = 55)

—————————

-31y = -31

-31y/-31 = -31/-31

y=1

4 0
3 years ago
The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu
mart [117]

Answer:

The shaded area is 23\ in^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

so

A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})

Calculate the shaded area

Remember that

3^{2}=9\\ 2^{2}=4

substitute

A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}

5 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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