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Aleks04 [339]
3 years ago
11

The length of a pole is to be 6.5 ft the actual length of the pole may vary by as much as 0.02 ft write an absolute value inequa

lity for the possible lengths of the pole
Mathematics
1 answer:
Tresset [83]3 years ago
5 0
 "<span>|x−6.5| ≤ 0.02" is the absolute inequality for the possible lengths of the pole.</span>
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Simplify the expression z2-z(z+3)+3z
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<span>z2-z(z+3)+3z
=> z2 - z2 - 3z + 3z 
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8 0
2 years ago
4/7 divided by 7/2?????
11Alexandr11 [23.1K]

Answer:

8/49

Step-by-step explanation:

4/7 ÷7/2

Copy dot flip

4/7 * 2/7

Multiply the numerators

4*2 = 8

Multiply the denominators

7*7= 49

numerator over denominator

8/49

8 0
2 years ago
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If he = 7x -27 find the value of x
Amiraneli [1.4K]

\\ \sf\longmapsto 7x-27=1

\\ \sf\longmapsto 7x=1+27

\\ \sf\longmapsto 7x=28

\\ \sf\longmapsto x=\dfrac{28}{7}

\\ \sf\longmapsto x=4

5 0
2 years ago
A student claims that the equation y=7 is not a linear equation because it does not have the form y=mx+b. Do you agree or disagr
Juliette [100K]
Disagree. Even  though it has no b  it is still a line but a horizontal line. It will be at 7 on the y- intercept but horizontal.
6 0
2 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
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