Question

Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?

Answer 1

Answer:

its B

1,215 1/5 x

Step-by-step explanation:

Answer 2

Answer:

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

$(\sqrt[5]{1215})^x$

We know that,

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Here, $n=5, a=1215$

So, $\sqrt[5]{1215} = 1215^{\frac{1}{5}}$

So, the above expression becomes:

$(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x$

Now, using the law of indices $(a^m)^n=a^{(m\times n)}$

Here, $a=1215,m=\frac{1}{5},n=x$

So, the expression is finally simplified to;

$=(1215)^{({\frac{1}{5}}\times x)}\\\\=(1215)^{\frac{1}{5}x}$

Therefore, the second option is the correct one.

$(\sqrt[5]{1215})^x$ = 1,215 Superscript one-fifth x