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navik [9.2K]
3 years ago
10

A bag contains 1 blue, 2 green, and 3 red marbles, as shown. What is the probability of drawing a green marble out of the bag wi

thout looking?
Mathematics
2 answers:
Doss [256]3 years ago
8 0

ANSWER

P(G)=  \frac{1}{3}

EXPLANATION

The number of green marbles in the bag is

n(G) = 2

The total number of marbles in the bag is

n(S)=1+2+3 = 6

The probability of selecting a green marble from the bag without looking is

P(G)=  \frac{n(G)}{n(S)}

Substitute the values to get,

P(G)=  \frac{2}{6}

P(G)=  \frac{1}{3}

horrorfan [7]3 years ago
3 0

Answer:

The probability of drawing a green marble out of the bag without looking = 1/3

Step-by-step explanation:

It is given that, a bag contains 1 blue, 2 green, and 3 red marbles

Therefore total number of marble in the  bag = 1 + 2 + 3 = 6

<u>To find the probability</u>

Total number of marble = 6

Number of green marble  = 2

The probability of drawing a green marble = 2/6 = 1/3

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