The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer: 7.22
(note: this is a result after rounding. The result before rounding was 7.21875)
========================================================
Explanation:
Given Set of Values = {22, 16, 39, 35, 19, 34, 20, 26}
Add up the values: 22+16+39+35+19+34+20+26 = 211
Divide that sum by 8 as there are 8 values: 211/8 = 26.375
The mean is 26.375
Now subtract the mean from each data value. Apply the absolute value to ensure the difference is never negative
|22 - 26.375| = 4.375
|16 - 26.375| = 10.375
|39 - 26.375| = 12.625
|35 - 26.375| = 8.625
|19 - 26.375| = 7.375
|34 - 26.375| = 7.625
|20 - 26.375| = 6.375
|26 - 26.375| = 0.375
Add up those results
4.375+10.375+12.625+8.625+7.375+7.625+6.375+0.375 = 57.75
Then divide by 8
57.75/8 = 7.21875
The mean absolute deviation of the prices is 7.21875
Rounded to two decimal places, it is 7.22
Since we're talking about money, it makes sense to round to the nearest penny.
I’m really late this time I’m sure you are alr done with your I ready lol
16ft and 25ft sorry if i’m wrong
Number of vertices of hexagon is 6
