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LiRa [457]
3 years ago
14

What number has the same value as 14 tens

Mathematics
1 answer:
tangare [24]3 years ago
8 0
If there are 14 tens, that is 14 multiplied by 10. 14 x 10 = 140.

140 is the answer.

Hope this helps :)
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Do the rational numbers form a finite set?
zysi [14]
Yea because the rationl numbers are diffrent form as a finite set 

6 0
3 years ago
M is the midpoint of AB. A is at (-5, 1) and M is (-1,4). Find the coordinates of B. Select one: O a (-3.2.5) O b.(-1.4) O c. (2
coldgirl [10]

Answer:

A (-3, 2.5)

Step-by-step explanation:

Midpoint formula is m=(x1 + x2/2), (y1 + y2/2)

So add the xs: -5 + -1 = -6

And the ys: 1 + 4 = 5

Then divide them by 2

(-3, 2.5)

4 0
3 years ago
What is the value of a in the equation 3a + b = 54, when b = 9?
sergey [27]
A = 15 3 x 15 + 9 = 54 keep up the good work!
3 0
3 years ago
Read 2 more answers
At central high school there are 398 sophomores who do not own a car and 29 who do there are 64 juniors who own a car and 339 wh
sertanlavr [38]

The proportion of sophomores that do not own a car is equal to 0.93.

<h3>What is ratio?</h3>

Ratio is a mathematical expression that is used to denote the proportion of two (2) or more quantities with respect to one another and the total quantities.

The proportion of sophomores that do not own a car is given by:

  • Number of sophomores that do not own a car = 398.
  • Total number of sophomores = 427

Therefore, proportion = 398/427 = 0.93.

The proportion of all students who are seniors who own cars is given by:

  • Number of seniors who own cars = 123
  • Total number of students = 1192

Therefore, proportion = 123/1192 = 0.10.

The proportion of non-car owners who are juniors is given by:

  • Number of juniors who are non-car owners = 339
  • Total number of students that do not own a car = 976.

Therefore, proportion = 339/976 = 0.35.

Read more on ratio here: brainly.com/question/13513438

#SPJ1

<u>Complete Question:</u>

At Central High School, there are 398 sophomores who do not own a car and 29 who do. There are 64 juniors who own a car and 339 who do not. There are 123 seniors who own a car, compared to 239 who do not. The above is a two-way table depicting this situation. Complete the following statements below by finding the ratio, then converting to a decimal. Round to the nearest hundredth.

The proportion of sophomores that do not own a car is?

The proportion of all students who are seniors who own cars is?

The proportion of non-car owners who are juniors is?

3 0
2 years ago
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
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