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docker41 [41]
4 years ago
12

1. A hot-air balloon flew at 10 miles per hour. Using the variable h, write and solve a multiplication equation to find how many

hours the balloon traveled if it covered a distance of 70 miles.
2. A passenger helicopter can travel 300 miles in the same time it takes a hot-air balloon to travel 20 miles. Using the variable s, write and solve a multiplication equation to find how many times faster the helicopter can travel than the hot air balloon.


Can you answer the two questions?? :/
Mathematics
1 answer:
Viktor [21]4 years ago
3 0
1. 10 x h=70      h= 7

2. 300 - 20=s   s= 280
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Please help meeeeeeeeee
Svetradugi [14.3K]

Answer:

x = 27

Step-by-step explanation:

Since l, m, and n are cut across by the two transversal lines, therefore, the transversal lines are cut off proportionally.

This implies that:

6/x = 10/45

Cross multiply

x*10 = 45*6

10x = 270

10x/10 = 270/10

x = 27

3 0
3 years ago
The first three steps of completing the square to solve the quadratic equation x^2 + 4x - 6 = 0, are shown below.
SpyIntel [72]
<span>The first three steps of completing the square to solve the quadratic equation x^2 + 4x - 6 = 0, are shown below.

step 1: x^2 + 4x = 6
step 2: x^2 + 4x + 4 = 6 + 4
step 3: (x + 2)^2 = 10
step 4: x + 2 = +/-sqrt(10)
step 5: x = sqrt(10) - 2, or x = -sqrt(10) - 2

so the steps are in order.</span>
5 0
3 years ago
Ronald runs 6,000 meters in 2 hours. He is thinking of running an 18 kilometers race. How much time will he take in the race if
babymother [125]

Answer:

6 hours

Step-by-step explanation:

speed = distance/ time

6000meters to km = 6000/1000= 6km

speed for the first race = 6/2

speed = 3km/hr

for the second race

speed = distance/time

3 = 18/time

cross multiply

3* t = 18

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t = 6 hours

7 0
3 years ago
Read 2 more answers
Rewrite the equation in polar form.
ycow [4]

Answer:

C) √5(cos(117°) +i·sin(117°))

Step-by-step explanation:

The rectangular number a+bi can be written in polar form as ...

√(a^2+b^2)×(cos(arctan(b/a)) + i·sin(arctan(b/a)))

Here, we have a=-1, b=2, so the magnitude is ...

√((-1)^2 +2^2) = √(1+4) = √5

and the angle is ...

arctan(2/(-1)) = arctan(-2) ≈ 116.565° . . . . . a 2nd-quadrant angle

Then you have ...

-1 +2i = √5(cos(117°) +i·sin(117°)) . . . . . . customary "polar form"

_____

Comment on the answer

The "polar form" is generally written as ...

(magnitude)·(cos(angle) +i·sin(angle))

You may also see it as ...

(magnitude) cis (angle) . . . . . . . where "cis" is shorthand for "cos + i·sin"

In my engineering courses, we often used the form ...

(magnitude) ∠ (angle)

The form used by my calculator is ...

(magnitude)·e^(i·angle) . . . . . where angle is usually in radians

4 0
3 years ago
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storchak [24]

Answer:

O-2(x+5)

Step-by-step explanation:

I have to much time on my hands

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3 years ago
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