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maksim [4K]
3 years ago
14

Find the coordinates of the midpoint of HK if H(-1,2) and K(-7,-4)

Mathematics
2 answers:
devlian [24]3 years ago
5 0
The coordinates would be at (-4.5,-1)
tankabanditka [31]3 years ago
5 0

Answer:

The midpoint of HK is (-4, 1)

Step-by-step explanation:

We are given two coordinates H(-1, 2) and K(-7, -4)

We need to find the midpoint of HK.

We have formula to find the midpoint.

(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} }

Here x_1 = -1, y_1 = 2, x_2 = -7 and y_2 = -4

Now plug in these values in the above formula, we get

(\frac{-1 + (-7)}{2} , \frac{2 +(-4)}{2} )

(\frac{-8}{2}, \frac{-2}{2}  ) =  (-4, -1)

So, the midpoint of HK is (-4, 1)

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I'LL GIVE BRAINLIEST !!! FASTER<br><br>please explain how do you get the answer !​
aliya0001 [1]

Answer:

70

Step-by-step explanation:

we have the angle of vertex in the isosceles triangle = 180-2*bottom coner= 180-65/2=50

3 angles in the equilateral triangle are equal to 60

we have 50 + 60 +h =the angle of PQR =180

h=70

7 0
3 years ago
Read 2 more answers
100 decreased by 50% and 150 decreased by 60%<br><br><br> Compare
sertanlavr [38]

Answer: 60% = 60/100 = 60 ÷ 100 = 0.6. 100% = 100/100 = 100 ÷ 100 = 1.

Step-by-step explanation: Decrease number by 60% of its value. Percentage decrease = 60% × 150 New value = 150

5 0
2 years ago
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)


5 0
3 years ago
7/12 divided by 3/4 is what?
Kisachek [45]
28/36 will be your answer which can be simplified into 14/18 which can be simplified again to 7/9 and that's your final answer
7 0
3 years ago
What is z if -1/3+2z=-5/6?
Wittaler [7]
-1/3+2z=-5/6
-2/6+2z=-5/6
Add 2/6 to both sides:
2z=-3/6
2z=-1/2
Divide both sides by 2
z=-1/4

Hope this helps :)
7 0
3 years ago
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