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steposvetlana [31]
3 years ago
6

3) -x + 5 = -11x + 25

Mathematics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

x=2

Step-by-step explanation:

-x+5=-11x+25

add +x on both sides -11x+x =-10x

-10x+25=5

subtract 25 on both sides

you get -10x=-20

x=2

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Sheri's freezer is 2 feet wide 6feet long and 2 feet deep what's the volume of her freeser
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2*6*2= 24

24 is the volume of Sheri's freeser

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Daniel works in a market. He has a large bag of potatoes that weighs 261/4 pounds and he is going to sell them in smaller bags o
Lynna [10]

Answer:

11 6/9

Step-by-step explanation:

Daniel works in a market

He has large bags of potatoes that weighs 26 1/4

Daniel is going to sell them in smaller bags 9/4 pounds each

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3 years ago
How many times dose 4<br> Go into 109
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Read 2 more answers
Use cross products to find the area of the triangle in the xy-plane defined by (1, 2), (3, 4), and (−7, 7).
Free_Kalibri [48]

I love these. It's often called the Shoelace Formula. It actually works for the area of any 2D polygon.


We can derive it by first imagining our triangle in the first quadrant, one vertex at the origin, one at (a,b), one at (c,d), with (0,0),(a,b),(c,d) in counterclockwise order.


Our triangle is inscribed in the a \times d rectangle. There are three right triangles in that rectangle that aren't part of our triangle. When we subtract the area of the right triangles from the area of the rectangle we're left with the area S of our triangle.


S = ad - \frac 1 2 ab -  \frac 1 2 cd - \frac 1 2 (a-c)(d-b) = \frac 1 2(2 ad - ab -cd - ad +ab +cd -bc) = \frac 1 2(ad -bc)


That's the cross product in the purest form. When we're away from the origin, a arbitrary triangle with vertices A(x_1, y_1), B(x_2, y_2), C(x_3, y_3) will have the same area as one whose vertex C is translated to the origin.


We set a=x_1 - x_3, b= y_1  - y_3, c=x_2 - x_3, d=y_2- y_3


S= ad-bc=(x_1 - x_3)(y_2 - y_3) -(x_2-x_3)(y_1 - y_3)


That's a perfectly useful formula right there. But it's usually multiplied out:


S= x_1y_2 - x_1 y_3  - x_3y_2 + x_3 y_3 - x_2 y_1 + x_2y_3 + x_3 y_1 - x_3 y_3


S= x_1 y_2 - x_2 y_1  + x_2y_3 - x_3y_2   + x_3 y_1 - x_1 y_3


That's the usual form, the sum of cross products. Let's line up our numbers to make it easier.


(1, 2), (3, 4), (−7, 7)

(−7, 7),(1, 2), (3, 4),


[tex]A = \frac 1 2 ( 1(7)-2(-7) + 3(2)-4(1) + -7(4) - (7)(3)

8 0
4 years ago
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