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4 years ago

Does the volume of a cone stay the same if you add 1 unit to the radius and subtract 1 unit from the height

1 answer:

5 0

To answer the question we proceed as follows:
suppose a cone has a height x units and radius x units
volume will be:
v=1/3πr²h
V=1/3πx³ cubic units

when we add 1 unit to the radius and subtract 1 unit from the height the volume will be:
v=1/3π(x+1)²(x-1)
v=1/3π(x³+x²-x-1) cubic units

comparing the above values for volume we conclude that the volume will not be the same. This means the volume won't stay the same after changes.

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What two equivalent fraction for 1/5

Julli [10]

Answer:

2 over 10 and 4 over 20

Step-by-step explanation:

3 0

3 years ago

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2x + 3y = 12<br> Complete the missing value in the solution to the equation.<br> ,8)

Kamila [148]

Answer: -6

Step by step:
2x + 3(8) = 12
2x + 24 = 12
2x = -12
x = -6

7 0

4 years ago

X²(x-3x) is a polynomial of which degree?

zloy xaker [14]

Answer:

Step-by-step explanation:

We simply start by opening up the bracket

we have this as:

x^2(x-3x) = x^3 - 3x^2

The degree is simply the highest power of x

This is 3

3 0

3 years ago

i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%

Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

$\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}$

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

$\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}$

Thus, the required probability is 13.98% approximately.

Theref

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1 year ago

2737÷13 full workingout

zlopas [31]

210.53846

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3 years ago

Read 2 more answers