Answer:
area of the merry go round =πr²
=22/7×3²
=28.28
answer is option D
All real numbers.

Step-by-step explanation:
Distributive property: a(b+c)=ab+ac
Expand: 4(a+2)=4a+8
Expand again: 14-2(3-2a)=4a+8
4a+8=4a+8
You subtract by 8 from both sides of an equation.
4a+8-8=4a+8-8
Simplify.
4a=4a
Then, subtract by 4a from both sides of an equation.
4a-4a=4a-4a
Finally, simplify.
4a-4a=0
0=0
True
All real numbers is the final answer.
Hope this helps you!
Have a nice day! :)
Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC =
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
, written in vertex form is
, where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}
When the slope is zero, the line is horizontal. Its equation will be of the form
... y = constant
The y-value of your point is specified as -9, so the equation of the line through that point is
... y = -9