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Rom4ik [11]
3 years ago
11

8 is 32 times as many as 4

Mathematics
1 answer:
Ber [7]3 years ago
6 0
What’s the question on this??? I’m confused. Please lmk so I can help you get the right answers :)
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48 girls, 41 boys, and 5 teachers sat in the gym. Write the ratio of girls to boys in three ways.
Anika [276]

Answer:

D

Step-by-step explanation:

The answer is D because the question is asking for girls to boys. So anything that has 5 in it is wrong because it isn't asking for teachers, which eliminates A. So since it is asking <u>girls</u><u> </u><u>to</u><u> </u><u>boys</u> the number order has to be 48 then 41 because it is asking for girls first then to boys. So that makes B wrong. When it comes to the fraction part of the ratio the first number it is asking for (which is girls) <em><u>alwa</u><u>ys</u></em> goes on top. So that eliminates C which leaves only answer to be D.

7 0
3 years ago
Answer the questions. All help needed.
svp [43]

1. Multiply all the x and y by 2

M (-6,4)

A (-4,6)

T (-2,4)

H (-4,2)

2. They stayed in the same quadrants. The x and y values shifted.

3. Scale factor of 1/2

4. .....mayhaps?

4 0
3 years ago
PLEASE HELP!!!!!! the sum of a number times 10 and 15 is at most -17
Brilliant_brown [7]

Let the number = x

Writing the equation you have:

10x + 15 <= -17

Solve for x

Subtract 15 from both sides:

10x <= -32

Divide both sides by 10:

X <= -32/10

Simplify:

X <= -16/5 as a fraction or -3.2 as a decimal

3 0
3 years ago
Is 95/72 closer to 0, 1, 2 or 3
kozerog [31]
1.3 so closer to 1 !! Best of luck
6 0
3 years ago
Read 2 more answers
A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig
Anika [276]

Answer:  (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Sample size = 463

\mu=118\text{ minutes}

\sigma=65\text{ minutes}

Significance level : \alpha=1-0.99=0.01

Critical value : z_{\alpha/2}=z_{0.005}=\pm2.576

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0
3 years ago
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