Sure you could as long as you have the point.
for example let's say the slope is 2 and the point we are given is (4,4)
we know that:
plug in the values given
x=4
y=4
m=2
b, the y intercept equals -4.
so:
in this case
Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
Hey buddy I am here to help!
total outcomes r = 36
multiples of 3 = 3,6
total outcomes of multiple fo 3 = 12
12/36 = 1/3
1/3 is the answer
Hope it helps!
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Download photomath and it will give u step by step instructions
