Pls pls pls pls pls help me pls

Pls i need help real fast i have 3 min to submit this

Neko [114]

Answer:

I was having trouble submitting a text answer, so I attached a file. Hope it helps.

Step-by-step explanation:

6 0

2 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form $y = ax^2 + bx + c$ , its vertex form is obtained as:

$y = ax^2 + bx + c\\y =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2 )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$

For the form $y = a(x-h)^2 + k$ , the vertex has coordinates (h, k)

Thus, for the obtained equation $y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$ , we get the coordinates of vertex as:

$h = -b/2a$ , $k = c - a\times(b/2a)^2$

Thus, the coordinates of vertex of $y = ax^2 + bx + c$ is:

$(h,k) = (-b/2a, c - a \times (b/2a)^2 )$

The missing steps of work of Jan'ai are:

Begin to write a function in factored form. $f(x) = a(x+1)(x-5)$
Substitute x = 0, y = f(x) = -25 to determine a. $-25 = a(0+1)(0-5)$
Simplify and solve to find a. $a=5$
Rewrite the function. $f(x) = 5(x+1)(x-5)$
Rewrite in standard form. $f(x) = 5x^2-20x-25$
Find the x-coordinate of the vertex. $x = -20/2(5) = -20/10; x = -2$
Find the y-coordinate of the vertex.

$y = 5x^2-20x-25$

$y = 5(-2)^2-20(-2)-25$

$y = 35$

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function $f(x) = 5x^2-20x-25$ ,

Comparing this to $f(x) = ax^2 + bx + c$ , we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

6 0

3 years ago

Find the measure of exterior angle A. Show equations and all work that leads to your answer.

Morgarella [4.7K]

Fine but I ain't showing my work completely.

The sum of all ext. angles of a polygon = 360.

So, you make this formula and solve for x.

360 = 49 + (3x+30) + (14x+6) + (6x-3) + (4x+8)
360 = 49 + 27x + 30 + 6 -3 + 8
360 = 90 + 27x
270 = 27x
/27 /27
10 = x

Now substitute for angle A, which is (6x-3)
6x-3
6(10)-3
60-3
57

Therefore, angle A is 57 degrees.

8 0

4 years ago

Read 2 more answers

Marni has 11 ounces of walnuts. She needs 6 ounces for one recipe and \frac {1}{4} 4 1 pound for another. There are 16 ounces

Katena32 [7]

Answer:

Yes she has enough walnuts for her two recipes

Step-by-step explanation:

Total number of walnuts that Marni has = 11 ounces

She has two receipe

First recipe = 6 ounces

Second recipe = 1/4 pounds

Hence,

To find out if she has enough:.we add up the number of ounces from both recipes

The second recipe is in pounds hence, we convert to ounces.

1 pound = 16 ounces

1/4 pound =

Cross Multiply

= 1/4 pounds × 16 ounces/1 pound

= 4 ounces

Hence, we can add up now

First recipe + Second recipe

= 6 ounces + 4 ounces

= 10 ounces.

Since both recipes would require a total of 10 ounces of walnuts and Marin has 11 ounces, we can conclude that Marin has enough ounces of walnuts for her two recipes.

5 0

3 years ago

Read 2 more answers

Using the extended Euclidean algorithm, find the multiplicative inverse of a. 1234 mod 4321 b. 24140 mod 40902

horsena [70]

(a) The inverse of 1234 (mod 4321) is x such that 1234*x ≡ 1 (mod 4321). Apply Euclid's algorithm:

4321 = 1234 * 3 + 619

1234 = 619 * 1 + 615

619 = 615 * 1 + 4

615 = 4 * 153 + 3

4 = 3 * 1 + 1

Now write 1 as a linear combination of 4321 and 1234:

1 = 4 - 3

1 = 4 - (615 - 4 * 153) = 4 * 154 - 615

1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234

1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234

Reducing this leaves us with

1 ≡ -1082 * 1234 (mod 4321)

and so the inverse is

-1082 ≡ 3239 (mod 4321)

(b) Both 24140 and 40902 are even, so there GCD can't possibly be 1 and there is no inverse.

8 0

3 years ago