Answer:
a. a[1] = 3; a[n] = 2a[n-1]
b. a[n] = 3·2^(n-1)
c. a[15] = 49,152
Step-by-step explanation:
Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.
The first term is 3, and the common ratio is 2.
<h3>(a)</h3>
The recursive rule is ...
a[1] = 3
a[n] = 2×a[n-1]
__
<h3>(b)</h3>
The explicit rule is ...
a[n] = a[1]×r^(n-1)
a[n] = 3×2^(n-1)
__
<h3>(c)</h3>
The 15th term is ...
a[15] = 3×2^(15-1) = 3×2^14
a[15] = 49,152
Use the zeroes to figure this out... x=-18, y=9
Answer:
{x∈R | 
, x∉Z}
Step-by-step explanation:
Given the function y=3tan(2/3x)
We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers
Also, the roots of y=3tan(2/3x) is 
where n is an integer
Note that the domain of the function cannot be within
Therefore, {x∈R | , x∉Z}
Answer: Sine - Sin
Tangent - Tan - Cosine - Cos
or inverse Cos-1 - Sin-1 - Tan-1
Step-by-step explanation:
You would use Sine - Sin for Opposite over hypotenuse
to check it you'd use Sin-1 that is just Sine but inverse that helps you get the answer- I just learned this stuff so bare with me but all of it is the same
I'm hoping I helped give you a small clue
Answer:
all values of b
Step-by-step explanation:
6b < 36 or 2b + 12 > 6.
First solve the one on the left
6b < 36
Divide by 6
6b/6 < 36/6
b <6
Then solve the one on the right
2b + 12 > 6
Subtract 12 from each side
2b+12-12 >6-12
2b >-6
Divide by 2
2b/2 >-6/2
b >-3
b<6 or b >-3
Rewriting
b>-3 or b<6
b > -3 is an open circle at -3 with a line going to the right
b < 6 is an open circle at 6 with a line going to the left
The or means we add the lines together
We have a line going from negative infinity to infinity
all values of b
