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avanturin [10]
3 years ago
5

Write an equation for the polynomial function that has 2 and -3 + 5i as zero

Mathematics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

p(x) = {x}^{3}  + 4{x}^{2}  + 22x- 68

Step-by-step explanation:

We want to write an equation for the polynomial function with roots;

x = 2

and

x =  - 3 + 5i

Note that complex roots come in pairs and in conjugates.

Therefore

x =  - 3 - 5i

is also a root.

By the factor theorem:

(x-2), (x+3+5i), and (x+3-5i) are factors of the polynomial.

Let p(x) be the polynomial, then in factored form.

p(x) = (x - 2)(x + 3 + 5i)(x + 3 - 5i)

We expand now to get:

p(x) = (x - 2)( {x}^{2}  + 3x  -  5ix + 3x + 9 - 15i + 5ix + 15i + 25)

Simplify now

p(x) = (x - 2)( {x}^{2}  + 6x +34)

We expand further;

p(x) = x( {x}^{2}  + 6x + 34) - 2( {x}^{2}  + 6x + 34)

p(x) = {x}^{3}  + 6 {x}^{2}  + 34x - 2 {x}^{2}   - 12x  - 68

p(x) = {x}^{3}  + 4{x}^{2}  + 22x- 68

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