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netineya [11]
3 years ago
13

1. Pool Dimensions. The area of a rectangular

Mathematics
1 answer:
Irina18 [472]3 years ago
5 0

Answer: I think the length is 60.25 yd and the width is 19.75 yd

Step-by-step explanation: I formed a equation using the information that has been given.

Width : X

length : 1 + 3x

equation : (1 + 3x) + x = 80

Then, I added the like pairs ( 3x+x ). After, I subtracted 1 from 80 and got 79. Then I divided 79 and 4 (79/4) to get 19.75, which is my x value. later, I substituted the x value to the equation and received my answer.

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Which of the following are solutions to the equation below? Check all that apply. 4x2 - 81 = 0
Vinil7 [7]

Answer:

9/2 -9/2

Step-by-step explanation:

Hope this helps! ;-)

8 0
2 years ago
Solve (r-s) (s-t) (t-r)
Bezzdna [24]
(rs-s^2-rt +st)(t-r)
= ts^2-rt^2+st^2-sr^2-rs^2+tr^2


8 0
3 years ago
Let R be the shaded region bounded by the graphs of y = e^x, y = -1, x = 1, and the y-axis. R is the base of a solid with cross
Kruka [31]

Answer:

get a graphing caculator and type the numbers in the rectangle and see what you get

Step-by-step explanation:

6 0
2 years ago
You move down 6 units. You end at (10, 4). Where did you start?
Alexandra [31]

Answer:

(10,10)

Step-by-step explanation:

coordinates are (x,y)

x is horizontal(left and right), y is vertical (up and down)

going down 6 means subtracting 6 from the second number

lets reverse that to go up and add 6 back

4+6=10

so the original point was (10,10)

8 0
3 years ago
Read 2 more answers
If a right triangle has a hypotenuse equal to 17 and a leg equal to 15, find the third side.
Yanka [14]
Use the pythagorean theorem a.k.a{a}^{2} +  {b}^{2}  =  {c}^{2}
c is the hypotenuse while a & b are the legs
{15}^{2}   +  {b}^{2} =  {17}^{2}
225 + {b}^{2} = 289
subtract 225 from 289
{b}^{2}  = 64
square root both b and 64
the other leg is equal to 8
8 0
3 years ago
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