<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
<h2>
Answer:</h2><h2>(5,5)</h2><h2 /><h2>Hope this helps!!</h2><h2>
</h2>
Answer: C. -2 1/8
Step-by-step explanation:
<em>-5 - 3 = -2</em>
<em>5/8 - 1/2 = 1/8</em>
<em>-2 1/8</em>
Answer:
3rd one
Step-by-step explanation:
The volume of the balloon is 500 cubic inches after 20 seconds
<h3>How to determine the volume?</h3>
From the given graph, we have:
- Time on the x-axis
- Volume on the y-axis
Also from the graph, we have:
V(20) = 500
This means that:
The volume of the balloon is 500 cubic inches after 20 seconds
Read more about graphs at:
brainly.com/question/4025726
#SPJ1
