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Y_Kistochka [10]

3 years ago

7

Does anyone know how to do this ??

1 answer:

german3 years ago

8 0

Answer:

Step-by-step explanation:

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I know the answers but i need the work. plz help

inysia [295]

For number 3.

You add 8 to both sides as you need to separate the variable

4x-8=32
+8 +8

4x=32

now divide 32 by 4

x=8

for number 4

you use pemdas to multiply the parenthisis

2(x-5)=-20

(2•x)-(2•5)

2x-10=-20

then add 10 to both sides

2x-10=-20
+10 +10

2x=10

divide 10 by two

x=5

5 0

3 years ago

point C(4,2) divides the line segment joining points A(2,-1) and B(x,y), such that AC:CB=3.1. what are the coordinates of point

White raven [17]

Answer: $B(x,y)=B(\frac{14}{3},3)$

Step-by-step explanation:

$\frac{4-2}{3} =x-4\\2=3x-12\\14=3x\\\frac{14}{3}=x\\\\\frac{2-(-1)}{3}=y-2\\3=3y-6\\9=3y\\3=y$

6 0

3 years ago

What is the total number of different 10-letter arrangements that can be formed using the letters in the word FORGETTING?

velikii [3]

Answer:

1814400

Step-by-step explanation:

7 0

2 years ago

Which expression is equivalent to (7 – 3k) – (4 – 5k) – (6 – 2k)?

gladu [14]

Answer:

The right response is " $3(k-1)$ ". A further solution is given below.

Step-by-step explanation:

The given expression is:

⇒ $(7 -3k) - (4 - 5k) - (6 - 2k)$

On solving the above expression, we get

⇒ $7-3k-4+5k-6+2k$

⇒ $7-3k-10+7k$

⇒ $3k-3$

On taking "3" as common, we get

⇒ $3(k -1 )$

3 0

3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago