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3 years ago

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Mathematics

1 answer:

Shtirlitz [24]3 years ago

5 0

Answer:

Step-by-step explanation:

let CP=x Rs

3 % of x=9

x=9×100÷3=300

CP=300 Rs.

profit=6%

SP=300×106÷100=318 Rs

when profit =9%

SP=300×109÷100=327 Rs

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Consider the following information: Tony, Mike, and John belong to the Alpine Club. Every member of the Alpine club who is not a

zzz [600]

Answer:

ranslation into first order logic ,

Tony, Mike and John belong to Alpine club.

S1 Member (Tony)

S2 Member (mike)

S3 Member (john)

Every member of the Alpine club who is not a skier is a mountain climber

S4 \forallx(Member(x)\wedge~Skier(x)\supsetClimber(x))

Mountain climbers do not like rain

S5 \forallx(Climber(x) \supset ~Like(x,Rain))

Anyone who does not like snow is not a skier

S6 \forallx(~Like(x,snow) \supset ~ Skier(x))

Mike dislikes whatever Tony likes

S7 \forallx(Like(Tony,x) \supset ~ Like(mike,x))

And likes whatever Tony dislikes

S8 \forallx(~Like(Tony,x) \supset Like(Mike,x)

Tony likes rain and snow

S9 Like(Tony,rain)

S10 Like(Tony, snow)

From s10 we know that (I(tony),I(snow)) \in I(Like)

From s7 we know that for every assignment v

(D,I),v|= Like(tony,x)\supset ~Like(Mike,x)

(D,I),v|= Member(x) \wedge Climber(x) \wedge ~ Skier(x)

(D,I),v |= \existsx(Member(x)\wedgeClimber(x)\wedge~Skier(x))

Hence a member of Alpine club who is a mountain climber but not a skier

suppose we donot have S7 , we have only s1-s6 and s8-s10.

To prove , we have to produce interpretations as :

D ={ t,m,j,s,r }

Interpretations:

I(tony)=t, I(mike)=m, I(john)=j, I(snow)=s, I(rain)=r

I(member)= {t,m,j}

I(skier)= {t,m,j}

I(climber)= {}

I(Like)= {(t,s),(t,r),(m,s),(m,r),(m,m),(m,t),(m,j),(j,s)}

Hence a member of Alpine club who is a mountain climber but not a skier

4 0

4 years ago

What is 5 +10 - 20 x 4

aev [14]

Answer:

-65 is the right answerrr

7 0

3 years ago

Read 2 more answers

Which algebraic expression is a polynomial with a degree of 5?

Eddi Din [679]

The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.

Looking at each the polynomial:

3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)

2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)

8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4: Degree is 6 (look at 1st term)

–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5: Degree is 6 (look at 1st and last term)

Therefore, the answer is the second option:
2xy4 + 4x2y3 – 6x3y2 – 7x4

6 0

3 years ago

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Your friend Alex was solving the equation 2x^2+3x=20 and the work below. Tragically, she made an error in her work. First, expla

earnstyle [38]

Answer:

Her error is that For solving by Completing the square method.

She has not made the Coefficient of x² as 1.

Therefore,

$x=\dfrac{-3+13}{4}=\dfrac{10}{4}=2.5\ OR\ x=\dfrac{-3-13}{4}=\dfrac{-16}{4}=-4$