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coldgirl [10]
3 years ago
13

If the sum of the first two consecutive even integers is equal to three times the third what are the three integers?

Mathematics
1 answer:
OleMash [197]3 years ago
5 0

we are given

three consecutive even integers

Let's assume

first even integer is x

second even integer is x+2

third even integer is x+4

sum of the first two consecutive even integers is equal to three times the third so, we can get equation as

x+x+2=3(x+4)

now, we can solve for x

2x+2=3x+12

2x+2=3x+12

x=-10

so, we get

first integer is -10

second integer is -10+2=-8

third integer is -10+4=-6.................Answer

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2x^2(-5x^2-4)+4x^4 in simplist form, plz help
Vikki [24]

Answer:

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Step-by-step explanation:

Given expression is:

2x^2(-5x^2-4)+4x^4

In order to write the expression in simplest form we have to multiply the terms which needs to be multiplied.

So,

= -10x^4-8x^2+4x^4

Combining alike terms

= -10x^4+4x^4-8x^2\\=-6x^4-8x^2\\

Can also be written as:

= -2x^2(3x^2+4)

3 0
3 years ago
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professor190 [17]
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pickupchik [31]
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laila [671]

Answer:

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Step-by-step explanation:

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<u />a^2=b^2+c^2-2bc\cdot cos(A)

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Therefore, the length of line segment BC is about 8.2 units

8 0
2 years ago
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