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tresset_1 [31]
3 years ago
13

Evaluate f(x)=3x-6 when x=2 and x=-4

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

Step-by-step explanation:

Plug in the x

f(2) = 3(-4)-6

2 = -12 - 6

2 = -18

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A company is going to make an oil container in the shape of a cylinder. As shown below, the container will have a height of 7m a
olga2289 [7]

Step-by-step explanation:

For oil container in the shape of a cylinder

radius (r) = 6 m

height (h) = 7 m

TSA of Cylinder

= <em><u>2πr ( r + h) </u></em>

= 2 * 3.14 * 6 ( 6 + 7)

= 2 * 3.14 * 6 (13)

= 2 * 3.14 * 6 * 13

= 489.84 square meter

<em>Now, </em><em> </em>

the total cost of the steel will be $18,613.92.

= 18613.92/489.84

= $38

Thus, The TSA of a cylinder is 489.84 square meter and $38 will the steel cost per square meter.

5 0
4 years ago
T = i/pr is what formula?
irina [24]

Step-by-step explanation:

it is the formula to calculate the time

in the formula

t = I / pr

t stands for time.

I stands for interest.

p stands for principal.

r stands for rate.

Hope it helps. :)

5 0
3 years ago
Vanessa starts with 7 rabbits in a pen. 80 days later she has 14, and 160 days later she has 28. Which function can model this s
aivan3 [116]

Answer:

dddjhjhjjuy777777777777777777777777776666666666666666666666666666666666hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhffffffffffffffffffffffflol fk hahaharahahahahahahhaahahahahhahalo

Step-by-step explanation:

ddddddddddddddddddd

5 0
3 years ago
How do you solve h/-3=12?
zepelin [54]
H = -36
I hope this helps! 
5 0
3 years ago
Plz answer!! ASAP!!
Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

⇒ 15° = x°

∠ABC = (4(15°) + 2°) = 62°

∠DBE = 5(15°) – 13° = 62°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 62° + ∠CBE = 180°

⇒ ∠CBE = 118°

∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

3 0
3 years ago
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