Answer:
Step-by-step explanation:
Answer to Consider the area between the graphs x+6y=12 and x+4=y^2. ... This Can Be Computed As A Single Interval Where Alpha= Beta= And H(y)=
For this case, we must find the quadratic equation equivalent to:
![(x-4) ^ 2- (x-4) -6 = 0](https://tex.z-dn.net/?f=%28x-4%29%20%5E%202-%20%28x-4%29%20-6%20%3D%200)
By definition we have to:
![(a-b) ^ 2 = a^2-2ab + b ^ 2](https://tex.z-dn.net/?f=%28a-b%29%20%5E%202%20%3D%20a%5E2-2ab%20%2B%20b%20%5E%202)
So:
![(x-4) ^ 2 = x ^ 2-2 (x) (4) + 4 ^ 2 = x ^ 2-8x + 16](https://tex.z-dn.net/?f=%28x-4%29%20%5E%202%20%3D%20x%20%5E%202-2%20%28x%29%20%284%29%20%2B%204%20%5E%202%20%3D%20x%20%5E%202-8x%20%2B%2016)
So, we have:
![- * + = +\\- * - = +](https://tex.z-dn.net/?f=-%20%2A%20%2B%20%3D%20%2B%5C%5C-%20%2A%20-%20%3D%20%2B)
![x ^ 2-8x + 16-x + 4-6 = 0](https://tex.z-dn.net/?f=x%20%5E%202-8x%20%2B%2016-x%20%2B%204-6%20%3D%200)
Equal signs add up and the same sign is placed.
Different signs are subtracted and the sign of the major is placed.
![x ^ 2-9x + 14 = 0](https://tex.z-dn.net/?f=x%20%5E%202-9x%20%2B%2014%20%3D%200)
Answer:
![x ^ 2-9x + 14 = 0](https://tex.z-dn.net/?f=x%20%5E%202-9x%20%2B%2014%20%3D%200)
Answer:
did they give u some initial numbers to substitute with or something?
WQJAbnuhajle hove ukleg disklhdnd obisolsyhdgo fibpiouhod09ziusvcevn Step-by-step explanation:
Answer:
An independent clause is a group of words that contains both a subject and a predicate. It expresses a complete thought and can stand alone as a sentence. It can also be joined to other dependent or independent clauses to make a more interesting and complex sentence.Step-by-step explanation: