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tekilochka [14]
3 years ago
6

How many arangments of letters in PARALLEL

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0
There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360
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Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3

What this means is that, we have a summation of the observed data and a summation of the frequency of data.

The mean was calculated as

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Where Sum FX is 2604 and Sum F is 13

However, our calculation should now read thus,

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By cross multiplication we now have

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Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus

Sum FX = 14 x 201

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If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be

2814 - 2604 = 210

So the height of the new member added to the team is 210 cm.

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