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tekilochka [14]
3 years ago
6

How many arangments of letters in PARALLEL

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0
There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360
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Need an answer thanks
MatroZZZ [7]

Answer:

CE = 105

Step-by-step explanation:

CE = CD + DE , hence

6x = 4x + 8 + 27 ( subtract 4x from both sides )

2x = 35 ( divide both sides by 2 )

x = 17.5

⇒ CE = 6 × 17.5 = 105



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2 years ago
Find the total surface area of the net below.
lana [24]

Answer:

78,4 cm^2

Step-by-step explanation:

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1 year ago
If f(x) = –4x2 – 6x – 1 and g(x) = –x2 – 5x + 3, find (f – g)(x).
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(-4x^2 -6x -1) - (-x^2 -5x +3) = -3x^2 - x - 4
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Ulleksa [173]
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