How many arangments of letters in PARALLEL

1 answer:

5 0

There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360

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kompoz [17]

Answer:

The answer is

Step-by-step explanation:

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