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3 years ago

How many arangments of letters in PARALLEL

1 answer:

5 0

There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360

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True or False??<br> The more mass a body has, the less inertia it has.

OLEGan [10]

Answer:

false

Step-by-step explanation:

bc mass and inertia are directly proportional so if mass increase, inertial will be increase

I=mr2

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3 years ago

5. Find the slope of the line through the given points.<br> (10, 4), (4, 15)

Rama09 [41]

-11/6, is the slope and is simplified

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3 years ago

A carton can hold 100 unit cubes that measure 1 inch by 1 inch by 1 inch.Discribe the dimensions of the carton using unit cubes

tamaranim1 [39]

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4 years ago

In a fruit juice recipe, the ratio by volume of orange juice to pineapple juice to apple juice is 2:7:5. How many

Vlad [161]

If orange:pineapple:Apple juice ratio is
2:7:5, pineapple juice would make up 7/14 of the whole juice mixture, which equals to 1/2. 1/2 of 3 litres = 1.5 litres
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The answer would be B (1/2)

6 0

3 years ago

Read 2 more answers

When the population distribution is normal, the statistic median {|X1 − X tilde|, . . . , |Xn − X tilde|}/0.6745 can be used to

Andreyy89

Answer:

The corresponding point estimate is 0.882.

The sample standard deviation is 1.373.

Step-by-step explanation:

The data set is:

S = {25.01, 25.87, 26.34, 26.51, 26.75, 27.24, 27.40, 27.63, 27.83, 27.90, 28.08, 28.13, 28.37, 28.58, 28.59, 28.96, 29.20, 29.22, 29.38, 30.88}

Compute the mean as follows:

$\bar X=\frac{1}{n}\sum X\\\\=\frac{1}{20}\times [25.01+25.87+...+30.88]\\\\=\frac{1}{20}\times 557.87\\\\=27.8935$

Subtract the mean from each value and take the modulus of those values.

The new data set is:

S₁ = {2.8835, 2.0235, 1.5535, 1.3835, 1.1435, 0.6535, 0.4935, 0.2635, 0.0635, 0.0065, 0.1865, 0.2365, 0.4765, 0.6865, 0.6965, 1.0665, 1.3065, 1.3265, 1.4865, 2.9865}

Arrange these values in ascending order as follows:

S₂ = {0.0065 , 0.0635 , 0.1865 , 0.2365 , 0.2635 , 0.4765 , 0.4935 , 0.6535 , 0.6865 , 0.6965 , 1.0665 , 1.1435 , 1.3065 , 1.3265 , 1.3835 , 1.4865 , 1.5535 , 2.0235 , 2.8835 , 2.9865}

There are 20 observations in the data set.

The median value for an even set of values is the mean of the middle two values.

In this case the median will be the mean of the 10th and 11th observations.

$\text{Median}=\frac{10^{th}obs.+11^{th}obs.}{2}=\frac{0.6965+1.0665}{2}=0.8815\approx 0.882$

Thus, the corresponding point estimate is 0.882.

Compute the standard deviation as follows:

In set S₁ we computed the absolute mean deviations.

Now take the square of these values and divide by (n - 1) to compute the sample variance:

$\sigma^{2}=\frac{1}{n-1}\sum (|X_{i}-\bar X|)^{2}$

$=\frac{1}{20-1}\times [(2.8835)^{2}+(2.0235)^{2}+...+(2.9865)^{2}]\\\\=\frac{1}{19}\times 35.7953\\\\=1.88396$

Compute the sample standard deviation as follows:

$\sigma=\sqrt{\sigma^{2}}=\sqrt{1.88396}=1.373$

Thus, the sample standard deviation is 1.373.

6 0

3 years ago