The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.
The complete question is attached below.
<h3>What is the volume and surface area of the pyramid? </h3>
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
Then the volume of the pyramid will be
V = (L × B × H) / 3
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
Then the volume will be
V = (7 × 7 × 8) / 3
V = 392/3 cubic units
Then the surface area will be
SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)
SA = 189 square units
Then the correct option is A.
More about the volume and surface area of the pyramid link is given below.
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The length of b<span> is determined to be 7.56 centimeters.
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A is aldult tickets
b is child tickets
b = 2/3 a
7a + 12b = 90
7a + 12 x 2/3 a = 90
7a + 8a = 90
15a = 90
a = 6; b = 4
Answer: (4, -5)
Step-by-step explanation:
o(4, -5) is the answer because if you are going units down from the orgin of (0,0) you would end with a negative 5 and going right 4 units from orgin, you'll end up with a 4.
Answer:
(20,-4)
Step-by-step explanation:
We are given;
One end point as (2,5)
Point of division as (10,1)
The ratio of division as 4:5
We are required to calculate the other endpoint.
Assuming the other endpoint is (x,y)
Using the ratio theorem
If the unknown endpoint is the last point on the line segment;
Then;
=
+![\frac{5}{9}\left[\begin{array}{ccc}2\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
Therefore; solving the equation;

solving for x
x = 20
Also

solving for y
y= -4
Therefore,
the coordinates of the end point are (20,-4)