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3 years ago

How many arangments of letters in PARALLEL

1 answer:

5 0

There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.

The number of unique arrangements is 8!/(2!*3!) = 3,360

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2x-3y=6 whats the slope and y-intercept?

VARVARA [1.3K]

Answer:

The slope is 2/3 and the y-intercept is -2

Step-by-step explanation:

2x - 3y = 6

-2x -2x Subtract 2x from both sides

-3y = -2x + 6

y = 2/3x - 2 Divide both sides by -3 to get y by itself

The slope is 2/3 and the y-intercept is -2

7 0

3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

KonstantinChe [14]

Answer: x=5

Step-by-step explanation:

$\frac{2x+0.8}{9}=1.2$

$\mathrm{Multiply\:both\:sides\:by\:}9$

$\frac{9\left(2x+0.8\right)}{9}=1.2\cdot \:9$

$\mathrm{Simplify}$

$2x+0.8=10.8$

$\mathrm{Subtract\:}0.8\mathrm{\:from\:both\:sides}$

$2x+0.8-0.8=10.8-0.8$

Simplify

$2x=10$

$\mathrm{Divide\:both\:sides\:by\:}2$

$\frac{2x}{2}=\frac{10}{2}$

Simplify

$x=5$

7 0

3 years ago

Read 2 more answers

Use the image below to answer the following parts.

12345 [234]

Answer:

Step-by-step explanation:

Part A

Since, the given angles are formed at a point are on a straight line, sum of these angles will be 180°.

Part B

(3x - 5)° + (4x + 2)° + (2x + 3)° = 180°

9x = 180

x = 20

Part C

m∠ADB = (3x - 5)°

= (3×20 - 5)°

= 55°

m∠DBK = (4x + 2)°

= (4×20 + 2)°

= 82°

m∠KBC = (2x + 3)°

= (2×20 + 3)°

= 43°

6 0

3 years ago

Help me pls DO ALL for a brainlist and a thanks

densk [106]

1 3/6 = 4/6+5/6 ,
1 1/5 = 1/5 + 5/5 , 2/5 + 4/5
1 4/8 = 6/8+6/8 , 7/8+5/8

3 0

2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago