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KIM [24]
3 years ago
15

THIS IS WORTH 44 POINTS!!

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0
Hello there! 


Your answer would be 

CAT (top line) = DBU (bottom line)


CAT (bottom line) = BZS (top line)


Hope I helped!

Let me know if you need anything else!

~ Zoe
STatiana [176]3 years ago
6 0
Since the bottom row is the row that changed, I'm looking for "cat" in the top row

C        A       T
E        C       V

or 

A      Y    V
C      A    T
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Please help, lots of points offered. No scam answers.
Alchen [17]

Answer: 11

Step-by-step explanation: y^{2} = 121, y = \sqrt{121}, y = 11

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Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis?
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Answer:

THE ANSWER OM EDGE IS (C)

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Step-by-step explanation:

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Jamie needs some clothes for school. He will purchase 5 socks for $ 1.31 each, 3 dozen t-shirts at $ 2.34 a dozen, and a pair of
kaheart [24]

Answer:

he was a little bit off but he was close because it $26.95

Step-by-step explanation:

1. 5 x 1.31= 6.55

2.  3x2.34=7.02

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6,632,512 what is the value o 3
BlackZzzverrR [31]
3 in this problem is in the Ten thousands place.
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the point (3,-6) lies on the terminal side of angle 0. Find the exact value of the six trigonometric functions of 0. Sin cos tan
Shkiper50 [21]

ANSWER

See explanation

EXPLANATION

The point (3,-6) is the fourth quadrant.

In this quadrant only the cosine ratio and the secant ratio are positive.

The remaining four trigonometric ratios are negative.

The diagram is shown in the attachment.

We use the Pythagoras Theorem to find the hypotenuse, h.

{h}^{2}  =  {6}^{2}  +  {3}^{2}

{h}^{2}  = 36 + 9

{h}^{2}  = 45

h =  \sqrt{45}

h = 3 \sqrt{5}

\sin( \theta)  =   -  \frac{opp}{hyp}

\sin( \theta)  =   -  \frac{6}{3 \sqrt{5} }

\sin( \theta)  =   -  \frac{2 \sqrt{5} }{ 5 }

\sin( \theta)  =   -  \frac{2}{ \sqrt{5} }

\ cos(\theta)  =   \frac{adj}{hyp}

\ cos(\theta)  =   \frac{3}{3 \sqrt{5} }

\ cos(\theta)  =   \frac{1}{ \sqrt{5} }

\ cos(\theta)  =   \frac{ \sqrt{5} }{5}

\tan(\theta)= -  \frac{opp}{hyp}

\tan(\theta)= -  \frac{6}{3}  =  - 2

\csc(\theta)= -  \frac{hyp}{opp}

\csc(\theta)= -  \frac{3 \sqrt{5} }{6}  =  -   \frac{\sqrt{5} }{2}

\sec( \theta)  =   \frac{hyp}{adj}

\sec( \theta)  = \frac{3 \sqrt{5} }{3}  =  \sqrt{5}

\cot( \theta)  =  -  \frac{adj}{opp}

\cot( \theta)  =   - \frac{3}{6}  =  - \frac{1}{2}

6 0
3 years ago
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