Answer:
The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.
Step-by-step explanation:
Geometric sequence:
In a geometric sequence, the quotient of consecutive terms is the same. The nth term of a geometric sequence is given by:

In which
is the first term and
is the common ratio.
A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again.
This means that:

Then


First 5 terms:





Find the total distance the ball has travelled after it hits the ground the 5th time.

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.
Given:
Variable g is 8 more than variable w. ⇒ g = w + 8
Variable g is also 4 less than w ⇒ g = w - 4
g = w + 8 or w = g - 8
g = w - 4 or w = g + 4
-2<x<3 | *2
-4<2x<6 | +7
3< 2x+7< 13
3<10<13
The answer is C
It’s 30 months because 2.5 years old times 12 months in a year is 30
Answer:
g(t) - h(t) = -2t - 1
Step-by-step explanation:
g(t) - h(t) = t-3-3t+2
= -2t -1