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3 years ago

Which of the following is a common denominator of

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

Step-by-step explanation:

4 x 5 = 20

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5-(8v+5)= -4(1 + 3v)

Lilit [14]

5-(8v+5) = -4(1+3v)
5-8v-5 = -4 - 12v
-8v = -4 - 12v
4v = -4
v = -1

8 0

3 years ago

Read 2 more answers

Consider the figure shown below. Find the value of BL

Gnesinka [82]

Answer:

BL = 2

Step-by-step explanation:

Given:

AL = 3

AC = 10

BC = 9

AL = AM = 3 (tangents drawn form am external point)

CM = AC - AM

CM = 10 - 3

CM = 7

CM = CN = 7 (tangents drawn form am external point)

BN = BC - CN

BN = 9 - 7

BN = 2

BN = BL = 2 (tangents drawn form am external point).

BL = 2

7 0

3 years ago

Help asappppp? i’m having trouble on wat the 1/4 point is

blagie [28]

Answer:

(-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

(x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

M = (A+B)/2

A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

(Q -A)/(B -A) = 1/4

4Q -4A = B -A . . . . cross multipliy

Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

Q = (3M -B)/2 . . . . reduce the fractions

Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0

3 years ago

James has 6 stamps in his stamp collection. Roy has 12 stamps in his stamp collection. James adds 2 stamps to his stamp collecti

Yuliya22 [10]

For every one stamp James has Roy has twice as much. So the ratio would be 1/2. Hope this helped!

6 0

3 years ago

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

3 years ago