Positive 5/8 hope this helps :) uno reverse btw lol
You wrote it there yourself, at the beginning of your question.
You wrote E = I x R
Divide each side by ' I ' : E / I = R
That's what you're asking for. ^
The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
Learn more about cone here:
brainly.com/question/1082469
#SPJ1
Step-by-step explanation:
ax2 + bx + c = 0
x12 = (-b ± √D) / 2a , D = b2 - 4ac .
5x2 + 7x + 3 = 0
a = 5 , b = 7 , c = 3
D = 49 - 60 = - 11 , x1 = (-7 - i √11) / 10
x2 = (-7 + i √11) / 10
