Answer:
One solution
Step-by-step explanation:
5x + y = 8
15x + 15y = 14
Lets solve using substitution, first we need to turn "5x + = 8" into "y = mx + b" or slope - intercept form
So we solve for "y" in the equation "5x + y = 8"
5x + y = 8
Step 1: Subtract 5x from both sides.
5x + y − 5x = 8 − 5x
Step 2: 5x subtracted by 5x cancel out and "8 - 5x" are flipped
y = −5x + 8
Now we can solve using substitution:
We substitute "-5x + 8" into the equation "15x + 15y = 14" for y
So it would look like this:
15x + 15(-5x + 8) = 14
Now we just solve for x
15x + (15)(−5x) + (15)(8) = 14(Distribute)
15x − 75x + 120 = 14
(15x − 75x) + (120) = 14(Combine Like Terms)
−60x + 120 = 14
Step 2: Subtract 120 from both sides.
−60x + 120 − 120 = 14 − 120
−60x = −106
Divide both sides by -60

Simplify

Now that we know the value of x, we can solve for y in any of the equations, but let's use the equation "y = −5x + 8"





















So there is only one solution to the equation.
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
Answer:
4
Step-by-step explanation:
(6^2) -5(6) -2 =4
that is the answer
19/25 is the answer
hope i helped!