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3 years ago

14

4 plus radical 3 times 4 plus radical 3

1 answer:

BigorU [14]3 years ago

3 0

Make a box, multiply, then add

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Anyone wanna help???

OLEGan [10]

Answer:

its probably the first 1

8 0

3 years ago

Read 2 more answers

Since the beginning of the year, 1982 people have come into a blood bank to donate blood and 340 were found to have high blood p

Alecsey [184]

Answer:

0.1715

Step-by-step explanation:

From previous experience 340/1982 is the past probability that a person has high blood pressure.

The division of that leads to 0.1715 that the next person will have high blood pressure. That number is roughly (very roughly) 1 person in 6. So if 6 people come in 1 will have high blood presure.

4 0

3 years ago

Solve: x + 1 < 5<br>Me confused and need help

natita [175]

Answer: x < 4

Step-by-step explanation: You are trying to isolate the variable, x, so you have to subtract 1 on both sides of the inequality. Then, you are left with x < 4.

4 0

3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

What is the initial term for the sequence<br> 36, 24, 16, ...?<br> ?

MariettaO [177]

Answer:

36

Step-by-step explanation:

The initial term is the very first term

36, 24, 16, ...?

has an initial term of 36

7 0

3 years ago