Answer:
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.
The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
The correct answer for the question that is being presented above is this one:
We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>
<span>Then set that equation equal to your solubility constant </span>
<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3
</span>
<span>So the molar solubility is 9.67x10-3</span>
Answer:3/4
Step-by-step explanation:
1x3=3
<span>1.Verify whether n is large enough to use the normal approximation by checking the two appropriate conditions.
<span>2.Translate the problem into a probability statement about X.</span></span>
