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3 years ago

What is the length of ML, in units?

Mathematics

1 answer:

RoseWind [281]3 years ago

8 0

Answer:

HJ = LK

HI=MK

JI=ML

ML=6 units

Hope this helps!

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In the congruent figures ABCD and WXYZ, which angles are corresponding?

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2 years ago

Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]

Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

$(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\$

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

$a-6 = -11\\a = -11+6\\a = -5$

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

#LearnwithBrainly

4 0

3 years ago

Consider Z1= 4-4 radical 3i and Z2= -16 i. What is Z1-Z2?

goldfiish [28.3K]

Answer:

Option (3)

Step-by-step explanation:

$Z_1=4-4\sqrt{3}i$

$Z_2=-16i$

$Z_1-Z_2=(4-4\sqrt{3}i)-(-16i)$

$=4-4\sqrt{3}i+16i$

$=4-(4\sqrt{3}i-16i)$

$=4-4(\sqrt{3}-4)i$

Therefore, Option (3) will be the correct option.

8 0

2 years ago