What is the geometric mean of 4 and 5

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Tatiana [17]

First you are going to look at the smallest box and figure out what the area is once you do that you will need to find the area of the bigger box once you figure out both of the areas you will then find out what they are you will then add up the amounts to get the area of both squares together

6 0

3 years ago

Identify the slope and y-intercept: y = -1/5x+12 Slope: y-intercept:

ipn [44]

Answer:

Slope: -1/5 y-intercept: 12

Step-by-step explanation:

y = -1/5x + 12

The equation given is the slope-intercept form, y= mx + b

In this equation, the m, or number in front of the x, is the slope of the line.

The b in the equation represents the y-intercept.

Therefore, according to the given equation, the slope is -1/5 and the y-intercept is 12.

8 0

3 years ago

Describe the solutions of each inequality in words: 2m ≥ 6

Semenov [28]

Answer:

Step-by-step explanation:

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Muévete para aquí, muévete para allá

Dame tu cosita (ay toma, cosita, cosita, cosita)

Dame tu cosita (ay toma, cosita, pure energy)

Dame tu cosita (ay toma, cosita, cosita, cosita)

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Dame tu cosita ah, ay

Dame tu cosita ah ah

Muévete para aquí, muévete para allá

Dame tu cosita (ay toma, cosita, cosita, cosita)

Dame tu cosita (ay toma, cosita, pure energy)

Dame tu cosita (ay toma, cosita, cosita, cosita)

8 0

3 years ago

A local Elementary School has 560 students. A Random Sample of 50

Komok [63]

Well since there was 560 students the it was 560/560. now that 50 got selected the total portion would be 560/6

7 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago