Five is twenty % of twenty-five
Answer:
Step-by-step explanation:
Prove that for any natural number 3^(n+4)-3n is divisible by 16.
(I'm going to assume that you mean 3^(n+4)-3^n.)
1. We can break up 3^(n+4)-3n into 3^n * 3^4-3^n (by the rule a^b*a^c = a^b+c).
2. Solve to get 3^n * 81 - 3^n
3. Factor out the 3^n, and you'll get 3^n(81-1), and simplify: 3^n(80)
You may notice that 80 is divisible by 16.
4. Rewrite what we got from the last step as: 3^n*5(16).
Hope this helped you!
dy/dx = 2xy
dy/y = (2x)dx
INT(1/y)dy = INT(2x)dx
ln y + c = x^2 + d
ln y = x^2 + constant
y = e^(x^2 + constant)
1 = e^constant ... so constant=0 ... so y = e^(x^2)
Verification:
y = e^(x^2)
dy/dx = 2x*e^(x^2) = 2xy
<span>and e^(0^2) = e^0 = 1
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<span>A product goes from $25 to $27 in price. the product has a percent increase of
Answer: </span><span>an increase of 8%</span>
Answer:
answer is 2
Step-by-step explanation:
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