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nignag [31]
3 years ago
13

I need help with this simplify problem​

Mathematics
1 answer:
nasty-shy [4]3 years ago
7 0

Answer:

Step-by-step explanation:

Numerator = y/ab - ab

   = y/ab - ab * ab/ab       (LCM = ab)

 =  (y - a²b²)/ab

Denominator = 1/a - a/b

                      = 1*b/a*b - a*a/b*a   (LCM = ab)

                      = (b-a²)/ab

(y/ab - ab ) / ( 1/a - 1/b) = (y - a²b²)/ab  *  ab/ (b-a²)

= (y - a²b²)/ (b-a²)

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Solve: x+2/x-4&lt;0<br> O _4 O -2 -2 -4
sammy [17]

Answer:

-2<x<4

Step-by-step explanation:

For \frac{x+2}{x-4} < 0, note that either the numerator or denominator is positive and the other must be negative for this inequality to be satisfied.

This means x+2>0 and x-4<0 or x+2<0 and x-4>0.

Lets look at the first scenario (x+2>0 and x-4<0)

x+2>0 and x-4<0

x>-2 and x<4

This means that -2<x<4.

Let’s look at the other scenario (x+2<0 and x-4>0)

x+2<0 and x-4>0

x<-2 and x>4

This means that x must be <-2 and >4 simualtaneously, which is impossible.

Therefore, this only occurs when -2<x<4.

I hope this helps! :)

7 0
3 years ago
The temperature is -4 it increases to 8 how many degrees did the temperature increase
Oliga [24]

Answer:

12 degrees.

Step-by-step explanation:

8 - (-4) = 12. So, the temperature increased by 12 degrees.

6 0
3 years ago
Please help me please ​
maxonik [38]

Answer:

F

Step-by-step explanation:

Hopefully this helps

8 0
3 years ago
First right answer gets brain
GalinKa [24]
The answer is C i think
6 0
4 years ago
Read 2 more answers
Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.
torisob [31]
Fermat's little theorem states that
a^p≡a mod p

If we divide both sides by a, then
a^{p-1}≡1 mod p
=>
a^{17-1}≡1 mod 17
a^{16}≡1 mod 17

Rewrite
a^{1000000} mod 17  as
=(a^{16})^{62500} mod 17
and apply Fermat's little theorem
=(1)^{62500} mod 17
=>
=(1) mod 17

So we conclude that
a^{1000000}≡1 mod 17

6 0
4 years ago
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