The answer for " J " would be 228
Answer is Y/2=51
We start with Y=102
We can plug 102 into the equation Y/2=?
We get 102/2=?
102/2=51.
Therefore, Y/2=51
Hello,
P(x)=x^4-6x²+2=(x-a)(x-b)(x-c)(x-d)
=x^4-(a+b+c+d)x^3+(ab+ac+ad+bc+bd+cd)x^2-(abc+abd+acd+bcd)x+abcd
==>
ab+ac+ad+bc+bd+cd=-6
abc+abd+acd+bcd=0
abcd=2
a+b+c+d=0 ==>(a+b+c+d)²=0=a²+b²+c²+d²+2(ab+ac+ac+bc+bd+cd)
==>a²+b²+c²+d²=0-2*(-6)=12
if a is a root P(a)=0==>a^4-6a²+2=0
if b is a root P(b)=0==>b^4-6b²+2=0
if c is a root P(a)=0==>c^4-6c²+2=0
if d is a root P(a)=0==>d^4-6d²+2=0
==>a^4+b^4+c^4+d^4-6(a²+b²+c²+d²)+4*2=0
==>a^4+b^4+c^4+d^4=-8+6*12=64
Answer:
No solution
Step-by-step explanation:
We have
For the sum it is not correct to assume
Note that for
it is assumed 
and in your case 
for 
In fact, considering a set 
we have
that satisfy 
This means that, by definition 
Therefore,
because the sum is empty.
For
we have other problems. Actually, this case is really bad.
Note that 
has no value. In fact, if we consider for the case
, the cosine function oscillates between ![[-1, 1]](https://tex.z-dn.net/?f=%5B-1%2C%201%5D)
, and therefore it is undefined. Thus, we cannot evaluate
and then
has no solution
