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4 years ago

What is the range of the function f(x)=-(x+3)^2+7

Mathematics

2 answers:

otez555 [7]4 years ago

7 0

Answer:

<em> All real numbers less than or equal to 7</em>

Step-by-step explanation:

we have

f(x)=-(x+3)^2+7

we know that

The function is a vertical parabola open downward

The vertex is the point ( -3,7 )

The vertex is a maximum

The range is the interval-----------> (-∞,7]

That means

All real numbers less than or equal to

kow [346]4 years ago

6 0

Answer: A: all real numbers less than or equal to 7

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Select the correct answer.<br> √3<br> 1,53<br> If the point<br> 3 is on the unit circle, what is x?

emmasim [6.3K]

If the point ( x, √3/ 3) is on the unit circle, then the value of x will be √2/ 3. The correct option is D.

<h3>What is the equation of the circle with radius r units, centered at (x,y)?</h3>

If a circle O has a radius of r units length and it has got its center positioned at (h, k) point of the coordinate plane,

then, its equation is given as:

$(x-h)^2 + (y-k)^2 = r^2$

The equation of unit circle is

$(x-h)^2 + (y-k)^2 = 1\\\\x^2 + \dfrac{\sqrt{3} }{3}^2 = 1\\\\x^2 + \dfrac{1 }{3} = 1\\\\\\x^2 = 1 - \dfrac{1 }{3} \\\\x^2 = 2/3\\$

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The correct option is D.

Learn more about the equation of a circle here:

brainly.com/question/10165274

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2 years ago