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3 years ago

10

Algebra 2 about domain and range

1 answer:

nekit [7.7K]3 years ago

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Write 7.104 as a fraction or mixed number

Amiraneli [1.4K]

7 with 13 over 125 this is the mixed number form.

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2 years ago

Read 2 more answers

Eighty-seven decreased by three times a number is greater than one hundred sixty-five

QveST [7]

The answer
the question is not clear
if it is to determine how to write this phrase as a mathematics equation, it is as follow:
let be x the unknown number
so <span>ighty-seven decreased by three times a number is greater than one hundred sixty-five means 87 - 3x>165,
so we can solve it easily as 87 - 165> 3x, and then 3 x > 32, and finally the value of x is x > 32/3=10.66</span>

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3 years ago

if angle A and angle B are supplementary, and angle A and angle C are supplementary. What conclusion is valid

Iteru [2.4K]

Answer:

Angle B and C are congruent.

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2 years ago

Jhony has ten apples he eats 1 how many does he have left

BlackZzzverrR [31]

its odd you're in high school and you're asking this but its 9

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2 years ago

baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago