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ValentinkaMS [17]
3 years ago
7

Need to finish this today ....

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

For this case, we have a scalene triangle, in which all its sides are different. Its three angles are also different.

We want to know what the smallest angle is.

<em>The smallest angle of a scalene triangle, is given by the angle that is in the vertex of the sides of greater length. </em>

In this case, the minor angle is B

Answer:

Option D

lesya692 [45]3 years ago
3 0
The correct answer is A
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What is the common multiples of 5,3,8
tangare [24]

Answer:

120.

Step-by-step explanation:

If you're asking for LCM the answer is 120.

3 0
3 years ago
Read 2 more answers
(-1, -5)<br><br><br> (-2, -4)<br><br><br> (-5,-1)<br><br><br> (-4, -2)
notka56 [123]

Answer:

  (-4, -2)

Step-by-step explanation:

  A = (-1, 2)

Add (-3, -4) to that and you get ...

  A' = (-1-3, 2-4) = (-4, -2) . . . . matches the last choice

__

The translation function has the effect of moving the point left 3 and down 4. You can count grid squares on the graph to see that A' ends up at (-4, -2).

8 0
3 years ago
Marta is making two different charms for necklace one charm has a 1 cm diameter and a 3.14 centimeter circumference A similar ch
dlinn [17]
Both charms are "similar".

And notice one diameter is 1, the other is 4, the diameters are on a ratio of 1:4 then, and so both figures are on a ratio of 1:4.

so, if another unit, like the circumference is at 3.14 on the small one, then the large one will have a circumference 4 times that much, because the circumferences are also on a 1:4 ratio.
4 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
Exponential growth/decay problem 1
RUDIKE [14]

Answer:

a) growth

b) $500

c) 6% = 0.06

d) f(x)=500(1.06)^x

e) $595.51

Step-by-step explanation:

<u />

<u>Part (a)</u>

Exponential GROWTH, since interest is applied to the account each year.

<u>Part (b)</u>

Initial amount = $500

<u>Part (c)</u>

Growth factor = 6% = 0.06 (in decimal form)

<u>Part (d)</u>

General form of exponential growth function:

f(x)=a(1+r)^x

where:

  • a = initial amount
  • r = rate of growth (in decimal form)
  • x = time (in years)

Given:

  • a = 500
  • r = 0.06

\implies f(x)=500(1+0.06)^x

\implies f(x)=500(1.06)^x

<u>Part (e)</u>

when x = 3

\begin{aligned}\implies f(3) & =500(1.06)^3\\ & = 595.51\: \sf(nearest\:hundredth)\end{aligned}

5 0
2 years ago
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