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o-na [289]
3 years ago
13

For a standard normal distribution, find the approximate value of P(-0.78 = z = 1.16). Use the portion of the standard normal ta

ble below to help answer the question.
(z)
0.00
0.16
0.22
0.78
1.00
1.16
1.78
2.00

(Probabilities)
0.5000
0.5636
0.5871
0.7823
0.8413
0.8770
0.9625
0.9772
Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Correction:

I think the question should be like that find the approximate value of

P(-0.78 < z < 1.16)?


Now,

the symbol Ф represent the cumulative density.

first find the

Ф(1.16) from the above given table which is equal to 0.8770.

Now,

find the Ф(-0.78) .

in our table we are given the value of Ф(0.78)=0.7823

so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177


P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)

= 0.8770-0.2177

= 0.6593

dalvyx [7]3 years ago
6 0

Answer: .... 66%....                            

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3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
nikitadnepr [17]

Answer:

The answer should be 45

Step-by-step explanation:

To get the whole are you would have to multiply the lenght with the Width and then take that answer and multiply it with the height

<u>BUT</u>

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a. There are 0 or 2 real positive roots for the equation and

b. There are 0 or 2 real negative roots for the equation.

<h3>What is the Descartes'rule of sign?</h3>

Descartes' rule of sign states that

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  • The number of real negative zero of a polynomial f(x) is the number of sign changes of the coefficients of f(-x) or an even number less than the number of sign changes of the coefficients of f(-x)

<h3>How to find the number of possible positive and negative roots are there for the equation?</h3>

Given the equation 0 = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1, writing it as a polynomial function, we have f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

<h3>a. The number of positive roots</h3>

So, to find the number of positive roots, we find the number of sign changes of the polynomial f(x).

So, f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

Since f(x) has coefficients -8, -2, + 8, -4, -1, there are two sign changes from -2 to + 8 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real positive roots.

So, there are 0 or 2 real positive roots for the equation.

<h3>b. The number of negative roots</h3>

So, to find the number of negative roots, we find the number of sign changes of the polynomial f(-x).

So, f(-x) = −8(-x)¹⁰ − 2(-x)⁷ + 8(-x)⁴ − 4(-x)² − 1

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Since f(x) has coefficients -8, +2, + 8, -4, -1, there are two sign changes from -8 to + 2 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real negative roots.

So, there are 0 or 2 real negative roots for the equation.

So,

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Learn more about Descartes' rule of sign here:

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