For a standard normal distribution, find the approximate value of P(-0.78 = z = 1.16). Use the portion of the standard normal ta
ble below to help answer the question.
(z)
0.00
0.16
0.22
0.78
1.00
1.16
1.78
2.00
(Probabilities)
0.5000
0.5636
0.5871
0.7823
0.8413
0.8770
0.9625
0.9772
2 answers:
Correction:
I think the question should be like that find the approximate value of
P(-0.78 < z < 1.16)?
Now,
the symbol Ф represent the cumulative density.
first find the
Ф(1.16) from the above given table which is equal to 0.8770.
Now,
find the Ф(-0.78) .
in our table we are given the value of Ф(0.78)=0.7823
so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177
P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)
= 0.8770-0.2177
= 0.6593
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