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zhuklara [117]
3 years ago
15

What is (6.3-5.1)×(0.3)

Mathematics
2 answers:
Alchen [17]3 years ago
8 0
0.36 is (6.3-5.1) times(0.3)
Paraphin [41]3 years ago
7 0
(6.3−5.1)×(0.3)
=0.36
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the length of a rectangle is six inches more than width, if the preimeter of the rectangle is 24 inches find the length
Nostrana [21]

Answer:

Length = 9 inches

Step-by-step explanation:

The perimeter of a rectangle is:

perimeter = 2(length + width)

24 = 2(a+b)

a = b + 6

a = length

b = width

then:

24 = 2((b+6)+b)

24/2 = b+6+b

12 = 2b + 6

12-6 = 2b

6 = 2b

b = 6/2

b = 3 inches

a = b+6

a = 3+6

a = 9 inches

Check:

24 = 2(9+3)

24 = 2*12

3 0
3 years ago
2 A rectangular computer screen has an area of A square inches. The width of the
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I wanna say it’s letter f or j I’m not sure.
5 0
3 years ago
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The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x
Marianna [84]
<span>You can use Heron's formula to solve this problem.

</span>A= \sqrt{s(s-a)(s-b)(s-c)} , where A is the area; a,b,с are the sides;  s<span> is the </span>semiperimeter<span> of the triangle
</span>s= \frac{a+b+c}{2}

<span>According to conditions:
</span>a = x
b = x+1
с = 2x-1

<span>Calculate the semiperimeter:
</span>s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x

<span>Now we can compose and solve the equation according to Heron's formula:
</span>\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10}   \\  \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\  \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\  \sqrt{2x^3-2x^2}=x \sqrt{10}  \  \  \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\  \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6

<span>As a result, x = 6 is your answer.
 
I hope this helped.</span>
7 0
3 years ago
Find the lenght of the missing side:
ollegr [7]

Answer:

x=15.73292

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos 70 = x / 46

46 cos 70 =x

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2 years ago
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Answer:

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