Ask question

Ask question

All categories

Gelneren [198K]

3 years ago

9

Robert and his friends are going into a grocery store. How much would it cost to buy 4 bananas and 5 peaches if each banana cost

s $0.40 and each peach costs $0.75? How much would it cost to buy 4 4 bananas and 5 5 peaches if each banana cost $ x $x and each peach cost $ y ? $y

1 answer:

Sati [7]3 years ago

6 0

Answer:

4*0.40+5*0.75=5.35

Step-by-step explanation:

You might be interested in

The federal government requires a car manufacturer to have a minimum miles per gallon (mpg) average over the models it makes. Su

valentinak56 [21]

Answer:

25 mpg

Step-by-step explanation:

We have a set of values 19, 21, 22, 28 and 18

The average (which is the mean of the set of values ) is :

19 + 21 + 22 + 28 + 18 = 21.6 mpg out of the government requirement

So we need a value such as the mean become at least 25 mpg

We have to solve the equation:

(19+21+22+28+ x)/ 5 = 25

(90 + x ) /5 = 25 ⇒ 90 + x = 125 ⇒ x = 35 mpg

If we get the mean of the set of values including 35 we have:

(19 +21+ 22+ 28 + 35 ) / 5 = 25 mpg government requirement

7 0

2 years ago

Dirk plants 12 seedlings in 8 min.

Slav-nsk [51]

The answer would be b 105

8 0

2 years ago

Read 2 more answers

Solve for x<br><br> 2cos(x + 40 ^ 0) = 1/2 for r 0<= x<=360^<br><br> Worth 6 marks

Mama L [17]

SOLVE THE EQUATIONS

6 0

2 years ago

Which Quadrant does the point (-3, 4) belong to? A. Quadrant I B. Quadrant II C. Quadrant III D. Quadrant IV

lubasha [3.4K]

We need a graph or picture then I can answer

7 0

2 years ago

Read 2 more answers

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

2 years ago