I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:
Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.
-- Their long sides are equal, OA = OB, because both of those lines
are radii of the big circle.
-- Their short sides are equal, OC = OC, because they're both the same line.
-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.
-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)
These triangles are not congruent the way they are now, because one is
the mirror image of the other one. But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.
So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
The car would travel 247.95 miles in 4 hours and 45 minutes
Repari cost (x) = y = 35.25 x + 40
x = number of hours to repair the car.
Every hour the cost will increase 35.25, becasue 40 is a fixed cost.
if x = 1, repair cost(1) = 35.25 + 40
if x = 2, repair cost (2) = 35.25*2 + 40
if you subtract repair cost (1) from repair cost (2) you get 35.25*2 - 35.25 = 35.25
The same thing every time the repair time increases one hour.
Answer: the last option of the list, for every hour of labor, the cost increases by $35.25
Answer:
No
Step-by-step explanation:
Assuming it take 1 buckle and 1 strap per collar, that means we just need to find the lowest common multiple of these 10-pack buckles and 12-pack straps.
For 10: 0, 10, 20, 30, 40, 50, "60", 70, 80, 90, 100...
For 12: 0, 12, 24, 36, 48, "60", 72, 84, 96, 108, 120...
From this, it is obvious that 60 is the lowest common multiple of these two numbers. Therefore, we know that Stefan can make dog collars without having leftover supplies by using 6 10-pack buckles and 5 12-pack straps.
From this, we know that Stefan does not need to buy 120 of either the buckles or the straps.
